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python实现七种列表去重方法

来源:哗拓教育
python实现七种列表去重⽅法

#encoding=utf-8import time

time_start=time.time()

print u\"列表去重的七种⽅法\"print u\"第⼀种测试⽅法\"repeat_list=[1,2,4,1,5,1,2,5]result=[]

for i in repeat_list: if i not in result: result.append(i)

print u\"第⼀种去重结果: \print u\"第⼆种测试⽅法\"repeat_list=[1,2,4,1,5,1,2,5]result={}

print u\"第⼆种去重结果: \print u\"第三种测试⽅法\"repeat_list=[1,2,4,1,5,1,2,5]

print u\"第三种去重结果: \print u\"第四种测试⽅法\"repeat_list=[1,2,4,1,5,1,2,5]import itertools

def test_groupby(x): if x==1:

print \"lower\" elif x>1 and x<4: print \"middle\" elif x>=4:

print \"higher\"

repeat_list=sorted(repeat_list)

data=itertools.groupby(repeat_list,key=test_groupby)for i,j in data: print list(j)

data=itertools.groupby(repeat_list)result=[]

for i,j in data:

result.append(i)

print u\"第四种去重结果: \print u\"第五种测试⽅法\"repeat_list=[1,2,4,1,5,1,2,5]

for i in [j for j in repeat_list if repeat_list.count(i)>1]: for x in range(repeat_list.count(i)-1): repeat_list.remove(i)

print u\"第五种去重结果: \print u\"第六种测试⽅法\"repeat_list=[1,2,4,1,5,1,2,5]i=0

while i<=len(repeat_list)-1:

if repeat_list.count(repeat_list[i])>1: repeat_list.pop(i) else: i+=1

print u\"第六种去重结果: \print u\"第七种测试⽅法\"repeat_list=[1,2,4,1,5,1,2,5]

func=lambda x,y:x if y in x else x + [y]

print u\"第七种去重结果: \print \"_\"*20

print u\"去重程序耗时%f\" % (time.time()-time_start)print \"_\"*20time.sleep(3)

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